- MATH.APP.160
- 7. Liitteet
- 7.1 Summaus
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Summaus¶
Kerrataan summausta ja summausmerkintää. Jos \(a_1,a_2,\ldots,a_n\) ovat reaalilukuja, niin merkitään
\[\sum_{i=1}^na_i=a_1+a_2+\cdots+a_n.\]
Esimerkiksi
\[\sum_{i=1}^{5}i^2=1^2+2^2+3^2+4^2+5^2=1+4+9+16+25=55.\]
Summausindeksin nimi voidaan valita vapaasti, joskin yleensä käytetään kirjainta \(i\), \(j\), \(k\), \(l\), \(m\) tai \(n\). Indeksointi voidaan aloittaa muustakin indeksistä kuin \(1\). Esimerkiksi edellinen summa voidaan kirjoittaa
\[\sum_{i=1}^5i^2=\sum_{k=1}^5k^2=\sum_{j=2}^6(j-1)^2=\sum_{j=0}^4(j+1)^2.\]
Jos termeillä on yhteinen tekijä \(c\), niin voidaan laskea
\[\sum_{i=1}^nca_i
=(ca_1)+(ca_2)+\cdots+(ca_n)
=c(a_1+a_2+\cdots+a_n)
=c\sum_{i=1}^na_i\]
eli
\[\sum_{i=1}^nca_i=c\sum_{i=1}^na_i.\]
Samaan tapaan saadaan
\[\sum_{i=1}^n(a_i+b_i)=\sum_{i=1}^na_i+\sum_{i=1}^nb_i.\]
Esimerkiksi
\[\sum_{i=1}^5(7i^2-4i)
=7\sum_{i=1}^5i^2-4\sum_{i=1}^5i
=7\cdot55-4\cdot15=325.\]
Tärkeä erikoistapaus on vakiotermin \(c\) summa
\[\sum_{i=1}^nc=\underbrace{c+c+\cdots+c}_{n\text{ kappaletta}}=nc.\]
Erityisesti
\[\sum_{i=1}^n1=n.\]
Merkin vaihtelu saadaan aikaan luvun \(-1\) potensseilla, sillä
\[\begin{split}(-1)^i =
\begin{cases}
-1,&\text{kun } i \text{ on pariton}\\
1,&\text{kun } i \text{ on parillinen.}
\end{cases}\end{split}\]
Esimerkiksi
\[\sum_{i=1}^5(-1)^ii=-1+2-3+4-5=-3\]
ja
\[\sum_{i=1}^5\frac{(-1)^{i+1}}{i^2}=1-\frac14+\frac19-\frac{1}{16}+\frac{1}{25}=\frac{821}{979}.\]
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